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$\log_{\tan x} (2 + 4 \cos^{2} x) = 2$ , then $x =$

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Correct option is D

We have logtanx2+4cos2x=2⇒2+4cos2x=tan2x⇒3+4cos2x=sec2x⇒4cos4x+3cos2x−1=0⇒4cos2x−1cos2x+1=0⇒cosx=±12

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logtanx2+4cos2x=2, then x=

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$\log_{\tan x} (2 + 4 \cos^{2} x) = 2$ , then $x =$