logtanx2+4cos2x=2, then x=
π4
π6
−π4
π3
We have logtanx2+4cos2x=2
⇒2+4cos2x=tan2x
⇒3+4cos2x=sec2x
⇒4cos4x+3cos2x−1=0
⇒4cos2x−1cos2x+1=0
⇒cosx=±12