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Logarithm of $32 \sqrt[5]{4}$ to the base $2 \sqrt{2}$ is

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3.6

5.6

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Correct option is A

Let x be the required logarithm, then by definition(22)x=3245⇒(2.21/2)x=25.22/5; ∴23x2=25+25Here, by equating the indices, 32x=275∴x=185=3.6.

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Logarithm of 3245 to the base 22 is

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Logarithm of $32 \sqrt[5]{4}$ to the base $2 \sqrt{2}$ is