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We have cos⁡y=32⇒ y=π6let cot⁡(x−y)=t∴        t2−t−3t+3=0⇒        (t−1)(t−3)=0∴        cot⁡(x−y)=1 or cot⁡(x−y)=3 Given that x∈(0,π)If x−y=π6 then x=π6+π6=π3⇒(x,y)=π3,π6If x−y=π4 then x=π6+π4=5π12⇒(x,y)=5π12,π6possible ordered pairs (x, y) are π3,π6,5π12,π6