The A.M of all the solutions of 4cos3x−4cos2x−cos(π+x)+1=0 in (0,315) is
49π
50π
51π
10π
4cos3x−4cos2x−cos(x+π)−1=0
4cos3x−4cos2x+cosx−1=0
4cos2xcosx-1+1cosx−1=0
cosx=1 has solutions as x=2π,4π,8π,....100π in (0,315)
∴ A.M=sum of numbersno. of numbers=2π+4π+......+100π50=51π