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$^{m} C_{r + 1} + = \sum_{k = m}^{n}^{k} C_{r} =$

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nCr+1

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Correct option is B

mCr+1+∑k=mn kCr=mCr+1+mCr+m+1Cr+…+n−1Cr+nCr=m+1Cr+1+m+1Cr+…+n−1Cr+nCr=m+2Cr+1+m+2Cr+…+n−1Cr+nCr ⋮ ⋮ ⋮ ⋮ ⋮=nCr+1+nCr=n+1Cr+1

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mCr+1+=∑k=mn kCr=

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$^{m} C_{r + 1} + = \sum_{k = m}^{n}^{k} C_{r} =$