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white counters and red counters are arranged in a straight line with counters on each side of a central mark. The number of ways of arranging the counters, so that the arrangements are symmetrical with respect to the central mark, is
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a
(m+n)!m!n!
b
2m+2nC2m
c
12(m+n)!m!n!
d
none of these
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Correct option is A
Arrange m white and n red counters on one side of the central mark. This can be done in (m+n)!m!n!Similar Questions
If then equal to
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