The major axis and minor axis of an ellipse are respectively, x - 2y - 5 - 0 and 2x + y + 10 = 0. If one end of latus rectum is (3 ,4), then the foci are
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a
(5, 0)
b
(-7, -6)
c
(-11, -8)
d
(11, 3)
answer is A.
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Detailed Solution
Foot of perpendicular from one end of latus rectum L(3, 4) on major axis which is focus is given byx−31=y−4−2=−(3−2(4)−5)12+(−2)2=2∴S(x,y)≡S(5,0)Another focus is image of s in the line 2x + y + 10 = 0.x−52=y−01=−2(2(5)+0+10)22+12=−8∴S′(x,y)≡S(−11,−8)
The major axis and minor axis of an ellipse are respectively, x - 2y - 5 - 0 and 2x + y + 10 = 0. If one end of latus rectum is (3 ,4), then the foci are