A man invites 6 non-vegeterian and 5 vegeterian friends for a dinner party. He arrange 6 non-vegeterian friends on one round table and 5 vegeterian friends along another round table. The number of ways this can be done is:

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11!

2880

8280

answer is C.

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Detailed Solution

Arrange non-vegeterians in (6 -1)! =5! ways and vegeterian in (5 – 1)! = 4! ways∴ required number of ways =(5!)(4!)=(120)(24)=2880

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