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A man invites 6 non-vegeterian and 5 vegeterian friends for a dinner party. He arrange 6 non-vegeterian friends on one round table and 5 vegeterian friends along another round table. The number of ways this can be done is:

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a
11!
b
9!
c
2880
d
8280

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detailed solution

Correct option is C

Arrange non-vegeterians in (6 -1)! =5! ways and vegeterian in (5 – 1)! = 4! ways∴ required number of ways =(5!)(4!)=(120)(24)=2880


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Three boys and three girls are to be seated around a circular table. Among them the boy X does not want  any girl as a neighbour and girl Y does not want any boy as a neighbour. The number of possible arrangement is:


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