First slide

Permutations

Question

A man invites 6 non-vegeterian and 5 vegeterian friends for a dinner party. He arrange 6 non-vegeterian friends on one round table and 5 vegeterian friends along another round table. The number of ways this can be done is:

Moderate

A

$11!$
B

9!
C

2880
D

8280

Solution

Arrange non-vegeterians in (6 -1)! =5! ways and vegeterian in (5 – 1)! = 4! ways
$∴$ required number of ways $= (5!) (4!) = (120) (24) = 2880$

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