A man is known to speak the truth 3 out of 4 times. He throws a die and reports that it is a six. The probability that it is actually 6 is

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answer is C.

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Detailed Solution

P(truth)=34 P(gets 6)=16 P(False)=14 P(not gets 6)=56 =34.1634.16+14.56 =38(by Bayes' theorem)

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