First slide
Arithmetic progression
Question

A man saves Rs. 200 in each of the first 3 months  of  his service. In each of the subsequent months his saving increases by Rs.40 more than the saving of immediately  previous month. His total saving from the  start of service will be Rs. 11040 after. 

Moderate
Solution

Total saving = 200+200+200+240+280+… to n months = 11040 

400+n22[400+(n3)40]=11040(n21)(n+26)=0n=21

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