Match the given lists.

a. We know that mCr+mCr−1×nC1+mCr−2×nC2+…+nCr=m+nCrSo, if m, n > r and m + n < r, then mCr+mCr−1×nC1+mCr−2×nC2+…+nCr=0b. If m, n > r then mCr+mCr−1×nC1+mCr−2×nC2+…+nCr=m+nCrc. If m, n < r < m + n then mCm×nCr−m+mCm−1×nCr−m+1+mCm−2×nCr−m+2+…+mCr−n×nCn=m+nCrd. If m