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The maximum possible number of points of intersection of 7 straight lines and 5 circles is: 

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a
111
b
109
c
107
d
105

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detailed solution

Correct option is A

Maximum possible number of points of intersection of 7 lines is  7C2=21 Maximum possible number of points of intersection of 5  circles in 2 5C2=20[∵ two circles can intersect in two distinct points.]Maximum possible number of points of intersection of 5 circles and 7 lines is 2(5) (7) = 70Thus, maximum possible number of points of intersection is  21 + 20 + 70 = 111.


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There are 15 points in a plane, no two of which are in a straight line except 4, all of which are in a straight line. The number of triangles that can be formed by using these 15 points is


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