The maximum possible number of points of intersection of 7 straight lines and 5 circles is:
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a
111
b
109
c
107
d
105
answer is A.
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Detailed Solution
Maximum possible number of points of intersection of 7 lines is 7C2=21 Maximum possible number of points of intersection of 5 circles in 2 5C2=20[∵ two circles can intersect in two distinct points.]Maximum possible number of points of intersection of 5 circles and 7 lines is 2(5) (7) = 70Thus, maximum possible number of points of intersection is 21 + 20 + 70 = 111.