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The maximum value of the function of in the interval [0, 1] is
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By Expert Faculty of Sri Chaitanya
a
20.4
b
2-0.4
c
1
d
20.6
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Correct option is C
f′(x)=0.6(1+x)−0.41+x0.6−0.6x−0.4(1+x)0.61+x0.62 =0.61+x0.6−x−0.4(1+x)11+x0.62(1+x)0.4 =0.61+x0.6x0.4−(1+x)1+x0.62(1+x)0.4x0.4 =0.6x0.4−11+x0.62(1+x)0.4x0.4<0∀x∈(0,1)Hence, f(x) is decreasing. Thus, f(x)max=f(0)=1
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