First slide
Equation of line in Straight lines
Question

The maximum value of y=(x3)2+x222x2+x212 is 

Difficult
Solution

y=f(x)=x222+(x3)2x2+x212

 Note that the first term describes the distance between Px,x2 and A(3,2) where as the second term describes the 

 distance between Px,x2 and B(0,1) . 

 Now PAPBAB for possible positions of P

 Hencef(x)max= distance between AB=9+1=10

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