The mean deviation of the data 3,10, 10,4,7,10, 5 from the mean is
2
2.57
3
3.75
Given, observations are 3, 10, 10, 4, 7 ,10 and 5. ∴ x=3+10+10+4+7+10+57=497=7
Now, M.D. =ΣdiN=187=2.57