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The mean deviation from mean of the observations  a,a+d,a+2d,,a+2nd is

a
n(n+1)d23
b
n(n+1)2d2
c
a+n(n+1)d22
d
None of these

detailed solution

Correct option is D

x¯=12n+1[a+(a+d)+…+(a+2nd)]=12n+1[(2n+1)a+d(1+2+…+2n)]=a+d2n2(2n+1)2n+1=a+nd∴MD from mean =12n+1Σxi−x¯=12n+12|d|(1+2+…+n)=n(n+1)|d|(2n+1)

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