First slide
Introduction to statistics
Question

The mean deviation from mean of the observations  a,a+d,a+2d,,a+2nd is

Moderate
Solution

x¯=12n+1[a+(a+d)++(a+2nd)]=12n+1[(2n+1)a+d(1+2++2n)]=a+d2n2(2n+1)2n+1=a+ndMD from mean =12n+1Σxix¯=12n+12|d|(1+2++n)=n(n+1)|d|(2n+1)

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