The mean deviation of an ungrouped data is 50. If each observation is increased by 2%, then the new mean deviation is

If x1…xn are the observations then the newobservations are (1.02)x1,(1.02)x2..,(1.02)xnTherefore the new mean =(1.02)x¯New mean deviation =1n∑(1.02)xi−(1.02)x¯                                  =(1.02)1n∑xi−x¯=(1.02)×50=51