The mean of n items is x¯. If the first term is increased by 1, second by 2 and so on, then the new mean is
x¯+n
x¯+n2
x¯+n+12
None of these
Let x1,x2,…xn be the n items.
Given, x¯=x1+x2+…+xnn
∴ New mean =x1+1+x2+2+…+xn+nn=x1+x2+…+xn+(1+2+…+n)n=x¯+n(n+1)2n [∵ from Eq. (i) ]=x¯+(n+1)2