The mean of 100 observations is 50 and their standard deviation is 5. The sum of squares of all the observations is
50000
250000
252500
255000
Given, x¯=50,n=100 and σ=5
⇒ 50=Σxi100⇒ Σxi=50×100=5000 Now, s 2=Σxi2n−(x¯)2⇒ 25=Σxi2100−(50)2⇒ 2525=Σxi2100∴ Σxi2=252500