The mean of 100 observations is 50 and their standard deviation is 5. The sum of squares of all the observations is
50000
250000
252500
255000
Given, x¯=50,n=100 and σ=5⇒50=Σxi100⇒Σxi=50×100=5000 Now, σ2=Σxi2n−(x¯)2⇒25=Σxi2100−(50)2⇒2525=Σxi2100∴ Σxi2=252500