Questions
Mean and standard deviation of 100 observations were found to be 40 and 10, respectively. If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 , respectively, find the correct standard deviation.
detailed solution
Correct option is B
∴ New mean, ∣x¯=100×40+3+27−30−70100=4000−70100=3930100 =39.3∵ Σx2=Nσ2+x¯2∴ =100(100+1600)=170000 New, Σx2=170000−(30)2−(70)2+(3)2+(27)2=170000−900−4900+9+729=164938∴ New, SD= New Σx2N−( New x¯)2=164938100−(39.3)2=1649.38−1544.49=104.89=10.24Talk to our academic expert!
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For (2n + 1) observations , and 0, where all x's are distinct, let SD and MD denote the standard deviation and median, respectively. Then which of the following is always true?
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