The mean value of the function f(x)=2ex+1 on the interval [0, 2] is
log2e2+1
1+log2e2+1
2+log2e2+1
2+loge2+1
Average = 12∫02 2ex+1dx=∫02 e−x1+e−xdx
=−log1+e−x02=log2−log1+e−2=2+log2/1+e2