The mean and the variance of a binomial distribution are 4 and 2 respectively. Then the probability of at least 2 successes is

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37/256

247/256

128/256

219/256

answer is B.

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Detailed Solution

Given that np=4, npq=2⇒q=12,p=12,n=8P(x≥2) = 1-P(x<2)=1−[P(x=0)+P(x=1)]=1−128 8C0+8C1=247256 ( formula Px=r=Cn,r qn-rpr

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