Q.
The mean and variance of n values of a variable x are 0 and 02, respectively. If the VariabLe y = x2 then mean of y is
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a
σ
b
σ2
c
1
d
None of these
answer is B.
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Detailed Solution
Given that, mean = 0 and variance =σ2( for x) Therefore, variance =σ2=Σx2n−Σxn2⇒ σ2=Σx2n−0 ⇒σ2=Σx2n Now, y=x2⇒ Σy=Σx2 ∴ y¯=Σx2n=σ2
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