Q.

The mean and variance of n values of a variable x are 0 and 02, respectively. If the VariabLe y = x2  then mean of y is

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a

σ

b

σ2

c

1

d

None of these

answer is B.

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Detailed Solution

Given that, mean = 0 and variance =σ2( for x) Therefore, variance =σ2=Σx2n−Σxn2⇒     σ2=Σx2n−0    ⇒σ2=Σx2n Now,         y=x2⇒        Σy=Σx2    ∴    y¯=Σx2n=σ2
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