Mean and variance of 20 observations are 10 and 4 respectively. It was found that in place of 11, 9 was taken by mistake. The correct variance, is
3.99
3.98
4.01
4.02
Let x1,x2,…,x20 be 20 observations. Then,
uncorrected ∑xi=20×10=200 and 120∑xi2−(10)2=4
⇒ uncorrected ∑xi2=2080
Corrected ∑xi=200−9+11=202
Corrected ∑xi2=2080−92+112=2120
∴ Correct variance =120 Corrected ∑xi− Corrected ∑xi202
=212020−202202=106−102.01=3.99