Q.

The mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, then P(X=7) is

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a

116

b

18

c

14

d

132

answer is D.

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Detailed Solution

μ=np=4 σ2=npq=2⇒q=12, p=12,  n=8 p(X=7)= 8C7(12)8=132
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