The mid points of the sides of a triangle are   (1,5,−1),(0,4,−2),(2,3,4) . The distance from origin to the farthest vertex from origin is

Given the midpoints of the sides of the triangle are D(1,5,−1),E(0,4,−2),F(2,3,4)If D,E,F are the sides of the triangle ABC then A=E+F-D=1,2,3 , B=D+F-E=3,4,5 and C=D+E-F=1,6,-7The distance of the vertices from the origin is OA=1+4+9=14OB=9+16+25=50OC=1+36+49=86The point C is farthest point from origin and at it is a distance 86