The middle term in the expansion of (x+1x)10  is

Given expansion is (x+1x)10   And  Index (n=10)  being an even number, there is Only one middle term namely (10+22)th  i.e. 6th  termWe have general term in the expansion (x+a)n (∴  Tr+1= nCr xn−r (a)r  be the expansion of (x+a)n)  T6  =T5+1= 10C5 (x)10−5 (1x)5  T6  =T5+1= 10C5 (x)5 (1x5) =10C5   The middle term in the expansion of (x+1x)10  is 10C5 .