The middle term in the expansion of (x2+1x2)2n  is

Given  expansion  (x2+1x2)2n  is  Here, the index is 2n , an even number, therefore, there is only one middle term Namely  (2n2+1)th  i.e. (n+1)th  term. We know that rth  term in the expansion of (x+a)n isTr+1=nCr xn−r ar ∴  Middle term Tn+1= 2nCn (x2)2n−n (1x2)n=Tn+1=2nCn (x)2n (x−2)n  Tn+1=2nCn