The minimum area (sq. units) of triangle formed by the tangent to the x2a2+y2b2=1 & coordinate axes is
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a
ab
b
a2+b22
c
(a+b)22
d
a2+ab+b23
answer is A.
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Detailed Solution
Any tangent to the ellipse x2a2+y2b2=1 at P(acosθ,bsinθ) is xcosθa+ysinθb=1 It meets co-ordinate axes at A(asecθ,0) and B(0,bcosecθ) Area of ΔOAB=12×asecθ×bcosecθ ( area )Δ=absin2θArea must be minimum when sin2θ is maximumsin2θ=1Therefore, minimum value of the area is ab square units