The minimum  distance between the line x−33=y−8−1=z−31  and x+3−3=y+72=z−64 is

Given lines are r→=3i^+8j^+3k^+l(3i^−j^+k^) and r→=−3i^−7j^+6k^+m(−3i^+2j^+4k^)Required shortest distance  =(6i^+15j^−3k^)⋅((3i^−j^+k^)×(−3i^+2j^+4k^))(3i^−j^+k^)×(−3i^+2j^+4k^) =|(6i^+15j^−3k^)⋅(−6i^−15j^+3k^)||−6i^−15j^+3k^| =36+225+936+225+9=270270=270=330