Q.
The minimum and maximum values of cosx+32sinx+π4+6 are
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a
1,11
b
11,-1
c
6,5
d
5,6
answer is A.
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Detailed Solution
cosx+3212sinx+12cosx+6=3sinx+4cosx+6 min value is c-a2+b2=6-32+22=6-5=1 Max value is c+a2+b2=6+32+22=6+5=11
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