Q.

The minimum and maximum values of cosx+32sinx+π4+6 are

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a

1,11

b

11,-1

c

6,5

d

5,6

answer is A.

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Detailed Solution

cosx+3212sinx+12cosx+6=3sinx+4cosx+6 min value is c-a2+b2=6-32+22=6-5=1 Max value is  c+a2+b2=6+32+22=6+5=11
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