The minimum number of terms of the series 1+ 3 + 9 + 27 + … so that the sum may exceed 1000, is
7
5
3
None of these
Let, the sum of n terms exceeds 1000.
Then 11−3n1−3>1000; or 3n−12>1000
or 3n>2001; but 36=729 and 37=2187;
∴n>6; but n is a positive integer
∴n=7,8,9,…
∴ The minimum number of terms = 7.