Questions
The minimum number of terms of the series 1+ 3 + 9 + 27 + … so that the sum may exceed 1000, is
detailed solution
Correct option is A
Let, the sum of n terms exceeds 1000.Then 11−3n1−3>1000; or 3n−12>1000 or 3n>2001; but 36=729 and 37=2187; ∴n>6; but n is a positive integer∴n=7,8,9,…∴ The minimum number of terms = 7.Similar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests