The minimum value of atan2⁡x+bcot2⁡x equals the maximum value of asin2⁡θ+bcos2⁡θ where a>b>0 then ab is

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answer is C.

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Detailed Solution

Minimum value of atan2⁡x+bcot2⁡x is 2abAnd maximum value of asin2⁡θ+bcos2⁡θ is a. ∵asin2⁡θ+bcos2⁡θ=(a−b)sin2⁡θ+b According to question, a=2ab∴ a=4b

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