The minimum value of the expression 2log10⁡x−logx⁡0.01 where x>1 is

2log10⁡x−log10⁡0.01log10⁡x, x>1=2log10⁡x+2log10⁡x=21y+y  where log10⁡x=y≥4 ∵1y+y≥2 for y=0, have log10⁡x>0