The minimum value of f(x)=|3−x|+|2+x|+|5−x| is:

f(x)={6−3x,        x<−210−x,       −2≤x<3x+4,         3≤x<53x−6,       x≥5 The function f is decreasing for x∈(−∞,3) and increases on (3,∞) . Hence, x=3 is a point of minimum and min f(x)=7