The minimum value of 27secx+64cosecx forx∈(0,π2) is_and is obtained at__

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25,tan−143

125,tan−1(43)

125,tan−1(34)

25,tan−1(34)

answer is B.

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Detailed Solution

Minimum value=(a23+b23)32=(9+16)32 , where a=27,b=64 =125minimum at x=tan−1ba3=tan−1(43)

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