Mr. A lives at origin on the Cartesian plane and has his office at (4$$, $$5). His friend lives at (2$$, $$3) on the same plane. Mr. A can go to his office traveling one block at a time either in the $$+y$$ or $$+x$$ direction. If all possible paths are equally likely then the probability that Mr. A passed his friends house is (shortest$$ path for any event must be $$considered)

Question

Infinity Learn · Accepted Answer

$$n(S)=9$$!$$4$$!$$.5$$!$$=126n(A)=O$$ to F and F to $$P=5$$!$$2$$!×$$3$$!×$$4$$!$$2$$!×$$2$$!$$=60$$⇒ $$P(A)=60126=1021$$

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material