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n arithmetic means are inserted between 3 and 17. If the ratio of first to last mean is 1 : 3, then n is equal to:
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a
4
b
5
c
6
d
8
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Correct option is C
Let the n arithmetic means between 3 and 17 be A1, A2,…, An If d is the common difference, then,d=17−3n+1=14n+1Also, A1An=13⇒3+d17−d=13⇒ 3+14/(n+1)17−14/(n+1)=13⇒3n+1717n+3=13⇒n=6Similar Questions
Between 1 and 31 are inserted M arithmetic means so that the ratio of the 7th and (M - 1) th means is 5:9, then the value of m is
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