Questions
is equal to
a
n
b
1n
c
1n+1
d
1n-1
detailed solution
Correct option is C
We know, (1−x)n=nC0−nC1x+nC2x2…(−1)nnCnxn On integrating limit 0 to 1, we get∫01 (1−x)ndx=∫01 nC0−nC1x+nC2x2…(−1)nnCnxndx →−(1−x)n+1n+101= nC0x− nC1x22+ nC2x33…(−1)nnCnxn−1n+101⇒0+1n+1=nC0− nC12+ nC23−…(−1)n nCnn+1Talk to our academic expert!
Similar Questions
If the coefficients of P th, ( p + 1)th and (p + 2)th terms in the expansion of (1 + x)n are in AP, then
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