Q.
nCr+2nCr−1+nCr−2 is equal to
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a
n+1Cr
b
nCr−1
c
n−1Cr−1
d
n+2Cr
answer is D.
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Detailed Solution
We have nCr+2nCr−1+nCr−2= nCr+nCr+1+ nCr−j+nCr−2=n+1Cr+n+1Cr−1=n+2Cγ
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