Q.

nCr+2nCr−1+nCr−2 is equal to

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a

n+1Cr

b

nCr−1

c

n−1Cr−1

d

n+2Cr

answer is D.

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Detailed Solution

We have  nCr+2nCr−1+nCr−2= nCr+nCr+1+ nCr−j+nCr−2=n+1Cr+n+1Cr−1=n+2Cγ
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nCr+2nCr−1+nCr−2 is equal to