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A 2n digit number starts with 2 and all its digits are prime, then the probability that the sum of any two consecutive digits of the number is prime is

a
4×2−3n
b
4×2−2n
c
2−3n
d
none of these

detailed solution

Correct option is A

The prime digits are 2, 3, 5, 7. If we fix 2 at first place, then other 2n - 1 places are filled by all four digits. So the total number of cases is 42n-1.Now, sum of 2 consecutive digits is prime when consecutive digits are (2,3) or (2, 5).Then 2 will be fixed at all alternative places.So favorable number of cases is 2n. Therefore, probability is2n42n−1=2n2−4n+2=222−3n=423n

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