First slide

Introduction to P.M.I

Question

$10^{n} + 3 (4^{n + 2}) + 5$ is divisible by $n \in N$

Moderate

A

7
B

5
C

9
D

17

Solution

On putting $n = 2 in 10^{n} + 3 (4^{n + 2}) + 5$ We get
$10^{2} + 3 \times 4^{4} + 5 = 100 + 768 + 5 = 873$
which is divisible by 9.

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