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a
2n(n+1)!
b
2n−1n!
c
2n+1n!
d
2n(n+2)!
answer is B.
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Detailed Solution
We have 1+xn=C0+C1x+C2x2+......+Cnxn(1+x)nn!=C0n!+C1n!x+C2n!x2+--+Cnn!xn If x=1, then 2nn!=1n!+1(n-1)!+12!(n-2)!+--- If x=-1, then 0=1n!-1(n-1)!+22!(n-2)!+… By subtracting, we get 2nn!=21(n-1)!+13!(n-3)!+….∴G.E.=2n-1n!