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For nN,15n5+13n3+715n is

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a
an integer
b
a natural number
c
a positive fraction
d
None of the above

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detailed solution

Correct option is B

Let P(n):15n5+13n3+715n∴ P(1)=15(1)5+13(1)3+7151 =15+13+715=3+5+715=1515=1∈NP(2)=15(2)5+13(2)3+7152 =325+83+1415 =96+40+1415=15015=10∈NBy mathematical induction P(n) is a natural number

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