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a
1/10
b
11/50
c
11/20
d
None of these
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Correct option is C
We have,x+100x>50or x2+100>50xor (x−25)2>525⇒x−25<525 or x−25>525⇒x<25−525 or 25+525 As x is a positive integer and 525=22.91, we must have x≤2 or x≥48. Thus, the favorable number of cases is 2+53==55 Hence, the required probability is 55/100=11/20.Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
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