For natural numbers m and n (1−y)m(1+y)n=1+a1y+a2y2+… and a1=a2=10, then (m,n) equals
(35, 45)
(20, 45)
(35, 20)
(45, 35)
(1−y)m(1+y)n=1−my+mC2y2−…(1+ny+nC2y2+… =1+(n−m)y+ nC2+mC2−mny2+……We are given n-m=a1=10and nC2+mC2−mn=a2=10⇒ n=m+10 and 12n(n−1)+12m(m−1)−mn=10⇒ (m+10)(m+9)+m(m−1)−2m(m+10)=20⇒ m2+19m+90+m2−m−2m2−20m=20⇒ −2m=−70⇒m=35.∴ n=45