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Q.

The negation of A→(A∨~B) is

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a

a tautologa

b

equivalent to (A∨~B)→A

c

equivalent to A→(A∧~B)

d

a fallacy

answer is D.

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Detailed Solution

A→(A∨~B)≡~A∨(A∨~B)≡(~A∨A)∨(~B)≡T∨(~B)≡T∴ Negative of A→A∨~B is ~T=F.
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