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The negation of  (pq)(p~r) is

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a
(~p∧~q)∨(p∧~r)
b
(~p∧~q)∧(~p∧r)
c
(~p∧~q)∨(~p∧r)
d
None of these

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detailed solution

Correct option is C

Let⁡S:(p∨q)    ∧(p∨~r)⇒     ~S:∼(p∨q)∨~(p∨~r)∴     ~S:(~p∧~q)∨(~p∧r)

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