Negation of the statement p→(q∧r) is
~p→∼(q∨r)
~p→∼(q∧r)
(q∧r)→p
p∧(~q∨~r)
We know that,~(p→q)≅p∧~q
∴∼(p→(q∧r)≅p∧(~(q∧r))≅p∧(~q∨~r) [by De-Morgan's laws ]